128 | 1 0 0 0 0 0 0 0
192 | 1 1 0 0 0 0 0 0
224 | 1 1 1 0 0 0 0 0
240 | 1 1 1 1 0 0 0 0
248 | 1 1 1 1 1 0 0 0
252 | 1 1 1 1 1 1 0 0
254 | 1 1 1 1 1 1 1 0
255 | 1 1 1 1 1 1 1 1
1.First query of Subnetting
192.168.0.10 (IP address )
255.255.255.192 (Subnet mask)
Now we have to calculate the How many host allot in per Network
256-192 = 64 (Host in Per Network) from 0 to 63 is total 64 i. e. 1 for Network ID and 1 for Broadcast ID and 62 is the HOST
(IP address is the Class C Address) We have to see the Host that is 192
ON Bits(1) ==> 2 (See in the Table 192 have 2 ON Bits)
OFF Bits (0) ==> 6 (See in the Table 192 have 6 OFF Bits)
Network ==> 2^X = 2^2==> 4
Host ==> 2^Y-2 = 2^6-2==> 62
1. Network Number 1
192.168.0.0 (Network ID)
192.168.0.1
192.168.0.2
192.168.0.3
192.168.0.4
192.168.0.5
.
.
.
.
192.168.0.58
192.168.0.59
192.168.0.60
192.168.0.61
192.168.0.62
192.168.0.63 (Broadcast ID)
2. Network Number 2
192.168.0.64 (Network ID)
192.168.0.65
192.168.0.66
192.168.0.67
192.168.0.68
.
.
.
.
.
192.168.0.123
192.168.0.124
192.168.0.125
192.168.0.126
192.168.0.127 (Broadcast ID)
3. Network Number 3
192.168.0.128 (Network ID)
192.168.0.129
192.168.0.130
192.168.0.131
192.168.0.132
.
.
.
.
192.168.0.187
192.168.0.188
192.168.0.189
192.168.0.190
192.168.0.191 (Broadcast ID)
4. Network Number 4
192.168.0.192 (Network ID)192.168.0.193
192.168.0.194
192.168.0.195
192.168.0.196
.
.
.
.
.
192.168.0.251
192.168.0.252
192.168.0.253
192.168.0.254
192.168.0.255 (Broadcast ID)
