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Problem 3.
192.168.10.0 /27 (IP Address)
So Subnet Mask is 255.255.255.224 (i.e. /27 )
224 means 3 ON bits and 5 OFF
Valid Subnets = 256-224 ==>32
Block :: 0 , 32 , 64, 96, 128, 160, 192, 224
Network = 2^3==>
host = 2^5-2==> 30
NETWORK 1
192.168.0.0 (Network ID)
192.168.0.1
192.168.0.2
192.168.0.3
192.168.0.4
.
.
.
.
192.168.0.27
192.168.0.28
192.168.0.29
192.168.0.30
192.168.0.31 (Broadcast ID)
NETWORK 2
192.168.0.32 (Network ID)
192.168.0.33
192.168.0.34
192.168.0.35
192.168.0.36
.
.
.
.
.
192.168.0.59
192.168.0.60
192.168.0.61
192.168.0.62
192.168.0.63 (Broadcast ID)
NETWORK 3
192.168.0.64 (Network ID)
192.168.0.65
192.168.0.66
192.168.0.67
192.168.0.68
.
.
.
.
.
192.168.0.91
192.168.0.92
192.168.0.93
192.168.0.94
192.168.0.95 (Broadcast ID)
NETWORK 4
192.168.0.96 (Network ID)
192.168.0.97
192.168.0.98
192.168.0.99
192.168.0.100
.
.
.
.
.
192.168.0.123
192.168.0.124
192.168.0.125
192.168.0.126
192.168.0.127 (Broadcast ID)
x
NETWORK 5
192.168.0.128 (Network ID)
192.168.0.129
192.168.0.130
192.168.0.131
192.168.0.132
.
.
.
.
192.168.0.155
192.168.0.156
192.168.0.157
192.168.0.158
192.168.0.159 (Broadcast ID)
NETWORK 6
192.168.0.160 (Network ID)
192.168.0.161
192.168.0.162
192.168.0.163
192.168.0.164
.
.
.
.
.
192.168.0.187
192.168.0.188
192.168.0.189
192.168.0.190
192.168.0.191 (Broadcast ID)
NETWORK 7
192.168.0.192 (Network ID)
192.168.0.193
192.168.0.194
192.168.0.195
192.168.0.196
.
.
.
.
.
192.168.0.219
192.168.0.220
192.168.0.221
192.168.0.222
192.168.0.223 (Broadcast ID)
NETWORK 8
192.168.0.224 (Network ID)
192.168.0.225
192.168.0.226
192.168.0.227
192.168.0.228
.
.
.
.
.
192.168.0.251
192.168.0.252
192.168.0.253
192.168.0.254
192.168.0.255 (Broadcast ID)