Subnetting Class C Address Problem 1

Problem 1.

192.168.10.0 /25  (IP Address)

So  Subnet Mask is  255.255.255.128 (i.e. /25 )

128 means 1 ON bit and  7 OFF
Host = 256-128 ==>128
Network = 2^X==>2^1 ==> 2

NETWORK 1

192.168.0.0 (Network ID)
192.168.0.1
192.168.0.2
192.168.0.3
192.168.0.4
.
.
.
.
192.168.0.123
192.168.0.124
192.168.0.125
192.168.0.126
192.168.0.127 (Broadcast ID)

NETWORK 2

192.168.0.128 (Network ID)
192.168.0.129
192.168.0.130
192.168.0.131
192.168.0.132
.
.
.
.
.
192.168.0.251
192.168.0.252
192.168.0.253
192.168.0.254
192.168.0.255 (Broadcast ID)