Subnetting Class B Address Problem 3

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Must Remind (Keep in Mind)

128 |  1 0 0 0 0 0 0 0   (i.e. 1 Bit ON and 7 OFF)

192 |  1 1 0 0 0 0 0 0   (i.e. 2 Bits ON and 6 OFF)

224 |  1 1 1 0 0 0 0 0    (i.e. 3 Bits ON and 5 OFF)

240 |  1 1 1 1 0 0 0 0    (i.e. 4 Bits ON and 4 OFF)

248 |  1 1 1 1 1 0 0 0    (i.e. 5 Bits ON and 3 OFF)

252 |  1 1 1 1 1 1 0 0    (i.e. 6 Bits ON and 2 OFF)

254 |  1 1 1 1 1 1 1 0    (i.e. 7 Bits ON and 1 OFF)

255 |  1 1 1 1 1 1 1 1    (i.e. 8 Bits ON and  0 OFF)

PROBLEM  3.

172.16.0.0 (Network Address)
255.255.224.0 (/19)

Network = 2^3 = 8
Hosts =      2^13 - 2 = 8190 ( 5 bits in 3rd octet and 8 bits in 4th octet)

valid subnets = 256-224=32. 

Block Size =  0 ,32, 64, 96, 128, 160, 192, 224   

NETWORK 1

172.16.0.0  (Network ID)
172.16.0.1  (First Host)
172.16.0.2
172.16.0.3
.
.
.
172.16.31.252
172.16.31.253
172.16.31254 (Last Host)
172.16.31.255 (Broadcast ID)

MUST READ

when the address 0.255  after that 3rd octet will be started from 1.0 then 1.1, 1.2, 1.3 similarly address reach 1.255  3rd octet will start From  2.0  Similarly  all the address will allocate in a same way. ( For Understanding the Procedure)

NETWORK  2

172.16.32.0  (Network ID)
172.16.32.1  (First Host)
172.16.32.2
172.16.32.3
.
.
.
172.16.63.252
172.16.63.253
172.16.63.254  (Last Host)
172.16.63.255  (Broadcast ID)

NETWORK  3

172.16.64.0  (Network ID)
172.16.64.1  (First Host)
172.16.64.2
172.16.64.3
.
.
.
172.16.95.252
172.16.95.253
172.16.95.254  (Last Host)
172.16.95.255  (Broadcast ID)

NETWORK  4

172.16.96.0  (Network ID)
172.16.96.1  (First Host)
172.16.96.2
172.16.96.3
.
.
.
172.16.127.252
172.16.127.253
172.16.127.254  (Last Host)

172.16.127.255  (Broadcast ID)

NETWORK  5

172.16.128.0  (Network ID)
172.16.128.1  (First Host)
172.16.128.2
172.16.128.3
.
.
.
172.16.159.252
172.16.159.253
172.16.159.254  (Last Host)

172.16.159.255  (Broadcast ID)

NETWORK  6

172.16.160.0  (Network ID)
172.16.160.1  (First Host)
172.16.160.2
172.16.160.3
.
.
.
172.16.191.252
172.16.191.253
172.16.191.254  (Last Host)

172.16.191.255  (Broadcast ID)

NETWORK  7

172.16.192.0  (Network ID)
172.16.192.1  (First Host)
172.16.192.2
172.16.192.3
.
.
.
172.16.223.252
172.16.223.253
172.16.223.254  (Last Host)

172.16.223.255  (Broadcast ID)

NETWORK  8

172.16.224.0  (Network ID)
172.16.224.1  (First Host)
172.16.224.2
172.16.224.3
.
.
.
172.16.255.252
172.16.255.253
172.16.255.254  (Last Host)

172.16.255.255  (Broadcast ID)

Subnetting Class B Address Problem 2

Must Remind (Keep in Mind)

128 |  1 0 0 0 0 0 0 0   (i.e. 1 Bit ON and 7 OFF)

192 |  1 1 0 0 0 0 0 0   (i.e. 2 Bits ON and 6 OFF)

224 |  1 1 1 0 0 0 0 0    (i.e. 3 Bits ON and 5 OFF)

240 |  1 1 1 1 0 0 0 0    (i.e. 4 Bits ON and 4 OFF)

248 |  1 1 1 1 1 0 0 0    (i.e. 5 Bits ON and 3 OFF)

252 |  1 1 1 1 1 1 0 0    (i.e. 6 Bits ON and 2 OFF)

254 |  1 1 1 1 1 1 1 0    (i.e. 7 Bits ON and 1 OFF)

255 |  1 1 1 1 1 1 1 1    (i.e. 8 Bits ON and  0 OFF)

PROBLEM  2.

172.16.0.0 (Network Address)
255.255.192.0 (/18)

Network = 2^2 = 4
Hosts =      2^14 - 2 = 16382 ( 6 bits in 3rd octet and 8 bits in 4th octet)

valid subnets = 256-192=64. 

Block Size =  0 , 64, 128   

That subetting is performing  in the third octet , So subnet are really 0.0 , 64.0 , 128.0 ,192.0 

NETWORK 1

172.16.0.0  (Network ID)
172.16.0.1  (First Host)
172.16.0.2
172.16.0.3
.
.
.
172.16.63.252
172.16.63.253
172.16.63.254 (Last Host)
172.16.63.255 (Broadcast ID)

MUST READ

when the address 0.255  after that 3rd octet will be started from 1.0 then 1.1, 1.2, 1.3 similarly address reach 1.255  3rd octet will start From  2.0  Similarly  all the address will allocate in a same way. ( For Understanding the Procedure)

NETWORK  2

172.16.64.0  (Network ID)
172.16.64.1  (First Host)
172.16.64.2
172.16.64.3
.
.
.
172.16.127.252
172.16.127.253
172.16.127.254  (Last Host)
172.16.127.255  (Broadcast ID)

NETWORK  3

172.16.128.0  (Network ID)
172.16.128.1  (First Host)
172.16.128.2
172.16.128.3
.
.
.
172.16.191.252
172.16.191.253
172.16.191.254  (Last Host)
172.16.191.255  (Broadcast ID)

NETWORK  4

172.16.192.0  (Network ID)
172.16.192.1  (First Host)
172.16.192.2
172.16.192.3
.
.
.
172.16.255.252
172.16.255.253
172.16.255.254  (Last Host)
172.16.255.255  (Broadcast ID)

Subnetting Class B Address Problem 1

Must Remind (Keep in Mind)

128 |  1 0 0 0 0 0 0 0   (i.e. 1 Bit ON and 7 OFF)

192 |  1 1 0 0 0 0 0 0   (i.e. 2 Bits ON and 6 OFF)

224 |  1 1 1 0 0 0 0 0    (i.e. 3 Bits ON and 5 OFF)

240 |  1 1 1 1 0 0 0 0    (i.e. 4 Bits ON and 4 OFF)

248 |  1 1 1 1 1 0 0 0    (i.e. 5 Bits ON and 3 OFF)

252 |  1 1 1 1 1 1 0 0    (i.e. 6 Bits ON and 2 OFF)

254 |  1 1 1 1 1 1 1 0    (i.e. 7 Bits ON and 1 OFF)

255 |  1 1 1 1 1 1 1 1    (i.e. 8 Bits ON and  0 OFF)

PROBLEM  1.

172.16.0.0 (Network Address)
255.255.128.0 (/17)

Network = 2^1 = 2
Hosts =      2^15 - 2 = 32766 ( 7 bits in 3rd octet and 8 bits in 4th octet)

valid subnets = 256-128=128. 

Block Size =  0 , 128   

That subetting is performing  in the tird octet , So subnet are really 0.0 and  128.0  These are the exact numbers we used with Class C we used that in the 3rd Octet then add 0 in the 4th Octet for the network address. (MUST READ)

Network1

172.16.0.0  (Network ID)
172.16.0.1
172.16.0.2
172.16.0.3
.
.
.
172.16.127.252
172.16.127.253
172.16.127.254
172.16.127.255 (Broadcast ID)

when the address 0.255  after that 3rd octet will be started from 1.0 then 1.1, 1.2, 1.3 similarly address reach 1.255  3rd octet will start From  2.0  Similarly  all the address will allocate in a same way. (MUST READ)

NETWORK  2


172.16.128.0  (Network ID)
172.16.128.1
172.16.128.2
172.16.128.3
.
.
.
172.16.255.252
172.16.255.253
172.16.255.254
172.16.255.255  (Broadcast ID)

Subnetting Class B Address

Must Remind (Keep in Mind)

128 |  1 0 0 0 0 0 0 0   (i.e. 1 Bit ON and 7 OFF)

192 |  1 1 0 0 0 0 0 0   (i.e. 2 Bits ON and 6 OFF)

224 |  1 1 1 0 0 0 0 0    (i.e. 3 Bits ON and 5 OFF)

240 |  1 1 1 1 0 0 0 0    (i.e. 4 Bits ON and 4 OFF)

248 |  1 1 1 1 1 0 0 0    (i.e. 5 Bits ON and 3 OFF)

252 |  1 1 1 1 1 1 0 0    (i.e. 6 Bits ON and 2 OFF)

254 |  1 1 1 1 1 1 1 0    (i.e. 7 Bits ON and 1 OFF)

255 |  1 1 1 1 1 1 1 1    (i.e. 8 Bits ON and  0 OFF)

CLASS B

255.255.0.0                                                 /16 

255.255.128.0                                             /17

255.255.192.0                                             /18

255.255.224.0                                             /19

255.255.240.0                                             /20

255.255.248.0                                             /21

255.255.252.0                                             /22

255.255.254.0                                             /23

Subnetting Class C Address Problem 4

192.168.10.0 /28  (IP Address)

So  Subnet Mask is  255.255.255.240 (i.e. /27 )

224 means 4 ON bits and  4 OFF

Valid Subnets = 256-240 ==>16

Block :: 0 ,16, 32,48 , 64,80, 96,112, 128,144, 160,176,192,208,224,240 

Network = 2^4==> 16

host = 2^4-2==> 14

NETWORK 1

192.168.0.0 (Network ID)
192.168.0.1
192.168.0.2
192.168.0.3
192.168.0.4
.
.
.
.
192.168.0.11
192.168.0.12
192.168.0.13
192.168.0.14
192.168.0.15(Broadcast ID)

NETWORK 2

192.168.0.16 (Network ID)
192.168.0.17
192.168.0.18
192.168.0.19
192.168.0.20
.
.
.
.
.
192.168.0.27
192.168.0.28
192.168.0.29
192.168.0.30
192.168.0.31 (Broadcast ID)

NETWORK 3

192.168.0.32 (Network ID)
192.168.0.33
192.168.0.34
192.168.0.35
192.168.0.36
.
.
.
.
.
192.168.0.43
192.168.0.44
192.168.0.45
192.168.0.46
192.168.0.47 (Broadcast ID)

NETWORK 4

192.168.0.48 (Network ID)
192.168.0.49
192.168.0.50
192.168.0.51
192.168.0.52
.
.
.
.
.
192.168.0.59
192.168.0.60
192.168.0.61
192.168.0.62
192.168.0.63(Broadcast ID)

NETWORK 5

192.168.0.64 (Network ID)
192.168.0.65
192.168.0.66
192.168.0.67
192.168.0.68
.
.
.
.
192.168.0.75
192.168.0.76
192.168.0.77
192.168.0.78
192.168.0.79(Broadcast ID)

NETWORK 6

192.168.0.80 (Network ID)
192.168.0.81
192.168.0.82
192.168.0.83
192.168.0.84
.
.
.
.
.
192.168.0.91
192.168.0.92
192.168.0.93
192.168.0.94
192.168.0.95 (Broadcast ID)

NETWORK 7

192.168.0.96 (Network ID)
192.168.0.97
192.168.0.98
192.168.0.99
192.168.0.100
.
.
.
.
.
192.168.0.107
192.168.0.108
192.168.0.109
192.168.0.110
192.168.0.111(Broadcast ID)

NETWORK 8

192.168.0.112 (Network ID)
192.168.0.113
192.168.0.114
192.168.0.115
192.168.0.116
.
.
.
.
.
192.168.0.123
192.168.0.124
192.168.0.125
192.168.0.126
192.168.0.127 (Broadcast ID)

NETWORK  9

192.168.0.128 (Network ID)
192.168.0.129
192.168.0.130
192.168.0.131
192.168.0.132
.
.
.
.
192.168.0.139
192.168.0.140
192.168.0.141
192.168.0.142
192.168.0.143 (Broadcast ID)

NETWORK 10

192.168.0.144 (Network ID)
192.168.0.145
192.168.0.146
192.168.0.147
192.168.0.148
.
.
.
.
.
192.168.0.155
192.168.0.156
192.168.0.157
192.168.0.158
192.168.0.159 (Broadcast ID)

NETWORK 11

192.168.0.160 (Network ID)
192.168.0.161
192.168.0.162
192.168.0.163
192.168.0.164
.
.
.
.
.
192.168.0.171
192.168.0.172
192.168.0.173
192.168.0.174
192.168.0.175 (Broadcast ID)

NETWORK 12

192.168.0.176 (Network ID)
192.168.0.177
192.168.0.178
192.168.0.179
192.168.0.180
.
.
.
.
.
192.168.0.187
192.168.0.188
192.168.0.189
192.168.0.190
192.168.0.191 (Broadcast ID)

NETWORK 13

192.168.0.192 (Network ID)
192.168.0.193
192.168.0.194
192.168.0.195
192.168.0.196
.
.
.
.
192.168.0.203
192.168.0.204
192.168.0.205
192.168.0.206
192.168.0.207 (Broadcast ID)

NETWORK 14

192.168.0.208 (Network ID)
192.168.0.209
192.168.0.210
192.168.0.211
192.168.0.212
.
.
.
.
.
192.168.0.219
192.168.0.220
192.168.0.221
192.168.0.222
192.168.0.223 (Broadcast ID)

NETWORK 15

192.168.0.224 (Network ID)
192.168.0.225
192.168.0.226
192.168.0.227
192.168.0.228
.
.
.
.
.
192.168.0.235
192.168.0.236
192.168.0.237
192.168.0.238
192.168.0.239 (Broadcast ID)

NETWORK 16

192.168.0.240 (Network ID)
192.168.0.241
192.168.0.242
192.168.0.243
192.168.0.244
.
.
.
.
.
192.168.0.251
192.168.0.252
192.168.0.253
192.168.0.254
192.168.0.255 (Broadcast ID)