Problem 2.
192.168.10.0 /26 (IP Address)
So Subnet Mask is 255.255.255.192 (i.e. /26 ) ( 255 means 8 bits ON and 192 means 2 bits ON )
(8+8+8+2 == 26)
192 means 2 ON bit and 6 OFF
Valid Subnets = 256-192 ==>64
Block :: 0 , 64 , 128, 192
Network = 2^2==>4
host = 2^6-2==> 62
NETWORK 1
192.168.0.0 (Network ID)
192.168.0.1
192.168.0.2
192.168.0.3
192.168.0.4
.
.
.
.
192.168.0.59
192.168.0.60
192.168.0.61
192.168.0.62
192.168.0.63 (Broadcast ID)
NETWORK 2
192.168.0.64 (Network ID)
192.168.0.65
192.168.0.66
192.168.0.67
192.168.0.68
.
.
.
.
.
192.168.0.123
192.168.0.124
192.168.0.125
192.168.0.126
192.168.0.127 (Broadcast ID)
NETWORK 3
192.168.0.128 (Network ID)
192.168.0.129
192.168.0.130
192.168.0.131
192.168.0.132
.
.
.
.
.
192.168.0.187
192.168.0.188
192.168.0.189
192.168.0.190
192.168.0.191 (Broadcast ID)
NETWORK 4
192.168.0.192 (Network ID)
192.168.0.193
192.168.0.194
192.168.0.195
192.168.0.196
.
.
.
.
.
192.168.0.251
192.168.0.252
192.168.0.253
192.168.0.254
192.168.0.255 (Broadcast ID)
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